Engineering
Chemistry
Compounds of Halogen Family
Hydrolysis
Compounds of Boron Family New
Question

Colum - I

(On hydrolysis)

Column - II
(A) NF3 (P) Hydrolysis is possible at room temperature.
(B) CCl4 (Q) It undergoes partial hydrolysis.
(C) 3SiF4 (R) Hydrolysis is possible at drastic condition.
(D) BiCl3 (S) One of the product is ionic.
  (T) One of the product HF.
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Solution
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Hydrolysis involves reaction with water. Let's analyze each compound:

(A) NF3: Hydrolysis is difficult due to low dipole moment and lack of vacant d-orbitals. It requires drastic conditions (R).

(B) CCl4: No hydrolysis occurs at room temperature as carbon has no vacant d-orbitals and is sterically shielded.

(C) SiF4: Undergoes complete hydrolysis at room temperature (P) due to vacant d-orbitals, producing H2SiF6 (ionic) (S) and HF (T). Reaction: 3SiF4+4H2O→2H2SiF6+H4SiO4

(D) BiCl3: Undergoes partial hydrolysis (Q) due to high polarizing power, forming BiOCl. One product is ionic (S).

Final Answer: (A)→(R); (B)→No match; (C)→(P),(S),(T); (D)→(Q),(S)