| Column - I | Column - II |
![]() |
(P) Aromatic compound |
![]() |
(Q) DBE ≥ 2 |
![]() |
(R) highest C–N bond order |
![]() |
(S) highest resonance energy |
| (T) compound which has at least one lone pair. |
Know your College Admission Chances Based on your Rank/Percentile, Category and Home State.
Get your JEE Main Personalised Report with Top Predicted Colleges in JoSA
This question tests aromaticity, DBE (Double Bond Equivalent), bond order, resonance energy, and lone pairs in nitrogen heterocycles.
Aromatic compounds follow Hückel's rule (4n+2 π-electrons), are planar, and cyclic. DBE is calculated as: , where C, H, X, N are atoms. Higher bond order indicates more double bond character. Resonance energy measures stability from delocalization.
Final Answer: The correct matches are determined by analyzing each structure's properties against the given criteria (P, Q, R, S, T).