Column I Column II (A) CH2 = CH2 (P) Br2 – H2O \overset{}{\rightarrow} decolourise (B) Me – C \equiv C – H (Q) Cold dil alkaline KMnO4 \overset{}{\rightarrow} decolourise (C) Me – C \equiv C – Me (R) NaNH2 \overset{\Delta}{\rightarrow} ppt. (S) NaHCO3 \overset{}{\rightarrow} CO2 \uparrow (T)

Engineering

Chemistry

Alkene

Alkyne

Question

Column I	Column II
(A) CH₂ = CH₂	(P) Br₂ – H₂O $\overset{}{\to}$ decolourise
(B) Me – C $\equiv$ C – H	(Q) Cold dil alkaline KMnO₄ $\overset{}{\to}$ decolourise
(C) Me – C $\equiv$ C – Me	(R) NaNH₂ $\overset{Δ}{\to}$ ppt.
	(S) NaHCO₃ $\overset{}{\to}$ CO₂ $↑$
	(T)

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A,B,C and D all are unsaturated so all will decolourwise Br₂/H₂O and cold dil. alkaline KMnO₄.
Terminal alkynes give ppt with NaNH₂. 2-alkynes are converted into 1-alkyne when heated with NaNH₂, So C will also give ppt.