Column-I Column-II Column-III (I) Concave Mirror (i) From –\infty to focus (P) Greater than v towards +\infty (II) Convex Mirror (ii) From focus to –\infty (Q) Lesser than v toward +\infty (III) Concave Lens (iii) From focus to pole/centre of lens (R) Greater than v away from +\infty (IV) Convex Lens (iv) From pole/centre of lens to focus (S) Lesser than v away from +\infty

Column-I	Column-II	Column-III
(I) Concave Mirror	(i) From – $\infty$ to focus	(P) Greater than v towards + $\infty$
(II) Convex Mirror	(ii) From focus to – $\infty$	(Q) Lesser than v toward + $\infty$
(III) Concave Lens	(iii) From focus to pole/centre of lens	(R) Greater than v away from + $\infty$
(IV) Convex Lens	(iv) From pole/centre of lens to focus	(S) Lesser than v away from + $\infty$

Linked Question 1

For the lens or mirror used in street light, find the right combination

(II) (i) (S)

(I) (i) (P)

(I) (ii) (S)

(II) (i) (R)

For convex mirror, $\frac{dv}{dt} = - \frac{v^{2}}{u^{2}} \frac{du}{dt} = - m^{2} \frac{du}{dt}$

m < 1 when object lies between $\infty$ and F and images moves from focus to pole.

Linked Question 2

For the lens or mirror used by dentists, find the right combination

(II) (iv) (R)

(II) (ii) (P)

(I) (iii) (R)

(I) (iv) (S)

for concave mirror,

m > 1 when object lies between F and pole and image moves from + $\infty$ to pole.

Linked Question 3

For the lens or mirror used in microscope, find the right combination

(IV) (iv) (S)

(IV) (ii) (Q)

(IV) (i) (P)

(IV) (iii) (R)

$for lens, \frac{dv}{dt} = m^{2} \frac{du}{dt};$

For convex lens, m > 1 when object moves from focus to centre of lens and image moves from + $\infty$ to centre of lens.