Engineering
Physics
Thermodynamics
Heat engine Refrigerator Entropy
Calorimetry
Question
10 gm of ice at 0°C is mixed with ‘m’ gm of water at 50°C. What is minimum value of m so that ice melts completely. (Lf = 80 cal/gm and sw = 1 cal/gm-°C)
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Solution
Heat required to melt 10 gm ice at 0°C = 10 × 80 = 800 cal
800 cal heat have to be absorbed from m gm water at 50°C
Then, 800 = m × 1 × 50, m = 16 gm
m = 16 gm