2CH3MgBr \underset{\left(\right. ii \left.\right) \textrm{ } H^{+}}{\overset{\left(\right. i \left.\right) \textrm{ } \left(CH\right)_{3} \left(ONH\right)

Engineering

Chemistry

Acid and Base GOC

Question

2CH₃MgBr $\underset{(ii) H^{+}}{\overset{(i) {CH}_{3} {ONH}_{2}}{\to}}$

CH₃–NH₂

CH₃–O–NH–CH₃

CH₃–NH–CH₃

CH₃–O–CH₃

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CH₃MgBr + CH₃ONH₂ → CH₄ + CH₃ONHMgCl

CH₃OH + CH₃–NH₂ $\overset{H_{3} O^{+}}{\leftarrow}$ CH₃NHMgCl + CH₃OMgBr

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