This question involves understanding the selective reduction of alkynes to alkenes using specific reagents. The key concept is that different catalysts/reagents give different stereochemical outcomes (cis or trans alkenes).

An alkyne (like 2-hexyne) can be reduced to an alkene (2-hexene) via catalytic hydrogenation. However, the stereochemistry of the product depends on the reagent used:

Step 1: Catalytic Hydrogenation with Pt or Pd
Common catalysts like Pt or Pd (e.g., Pt/H₂ or Pd/C) give complete reduction to the alkane. They are too reactive and do not stop at the alkene stage. Even Pd/BaSO₄ (Lindlar's catalyst) is used for reduction, but it gives the cis-alkene, not the trans isomer.

Step 2: Reduction with LiAlH₄
LiAlH₄ is a strong reducing agent used primarily for reducing carbonyl groups, carboxylic acids, etc. It is not generally used for reducing carbon-carbon triple bonds. It would not give the desired alkene product.

Step 3: Reduction with Li/NH₃ (lithium in liquid ammonia)
This is a dissolving metal reduction. The mechanism involves single electron transfers, forming a radical anion intermediate. The trans geometry is favored due to steric reasons in the intermediate. The reaction is:

$RC \equiv CR' \overset{1. Li, NH 3 (l)}{\to} trans-RCH = CHR'$

Thus, Li/NH₃ is the reagent that selectively reduces an internal alkyne to the trans-alkene.

Final Answer: The correct reagent is Li/NH₃ (lithium in liquid ammonia).

Related Topics & Formulae

Alkyne Reduction Reactions:

Complete Reduction to Alkane: H₂ with Pt, Pd, or Ni catalyst.
cis-Alkene Formation: H₂ with Lindlar's catalyst (Pd/BaSO₄, poisoned with quinoline).
trans-Alkene Formation: Li or Na in liquid NH₃ (dissolving metal reduction).

Mechanism Insight: The dissolving metal reduction (Li/NH₃) proceeds via a radical anion mechanism. An electron is transferred from Li to the alkyne, forming a radical anion. This anion is protonated by NH₃, and another electron transfer followed by protonation gives the trans-alkene due to the anti-addition.