3 g of activated charcoal was added to 50 mL of acetic acid solution (0.06N) in a flask. After an hour it was filtered and the strength of the filtrate was found to be 0.042 N. The amount of acetic acid adsorbed (per gram of charcoal) is :

Engineering

Chemistry

Adsorption

Concentration Terms

Question

3 g of activated charcoal was added to 50 mL of acetic acid solution (0.06N) in a flask. After an hour it was filtered and the strength of the filtrate was found to be 0.042 N. The amount of acetic acid adsorbed (per gram of charcoal) is :

18 mg

54 mg

42 mg

36 mg

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For acetic acid molarity = Normality

Initial millimoles of CH₃COOH = 50 × 0.06 = 3

Final millimoles of CH₃COOH = 50 × 0.042 = 2.1

Millimoles of CH₃COOH adsorbed = 3 – 2.1 = 0.9

Mass of CH₃COOH adsorbed = $\frac{0 .9}{1000} \times 60 = 54 \times 10^{- 3} g$ = 54 mg

Mass of CH₃COOH adsorbed per gram charcoal = $\frac{54}{3} mg$ = 18 mg