Engineering
Chemistry
First Law and Various Process
Question

5 moles of an ideal gas at 100 K are allowed to undergo reversible compression till its temperature becomes 200 K . If CV = 28 JK–1 mol–1, calculate ΔU and ΔPV for this process. (R = 8.0 JK–1mol–1)

ΔU = 14 kJ : Δ(PV) = 4 kJ

ΔU = 14 kJ : Δ(PV) = 18 kJ

ΔU = 14 J : Δ(PV) = 0.8 J

ΔU = 2.8 kJ : Δ(PV) = 0.8 kJ

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Solution

ΔU = nCvm × ΔT

= 5 × 28 ×100 = 14 kJ

ΔPV = nRΔT

= 5 × 8 × 100 = 4 kJ