Engineering
Mathematics
Introduction to Determinants
Question

A=[891011], then cofactor of a12 is :

11
10

– 11

– 10

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Solution
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By property of cofactor (2),
A=[891011]
minor of a12 = M12 = 10
So, cofactor of a12 = M12(– 1)1+2 = – M12 = – 10

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