A 20 ml sample of Cu2+ solution was diluted to 250 ml. A portion of this solution was found to have an absorbance of 0.15 under the same condition that were used to generate the given absorbance vs [Cu2+] graph what was the concentration of Cu2+ ions in the original sample.

Engineering

Chemistry

Percentage Yield

Concentration Terms

Solution Stoichiometry

Question

A 20 ml sample of Cu²⁺ solution was diluted to 250 ml. A portion of this solution was found to have an absorbance of 0.15 under the same condition that were used to generate the given absorbance vs [Cu²⁺] graph what was the concentration of Cu²⁺ ions in the original sample.

0.075 M

0.006 M

0.94 M

0.3 M

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[Cu²⁺] in the original sample = $(\frac{0 .075 \times 250}{20}) \approx 0 .94 M$