A bag contains 5 red balls and 8 blue balls. It also contains 4 green and 7 black balls. If a ball is drawn at random, then find the probability that it is not green.

Engineering

Mathematics

Conditional Probability

Question

$\frac{5}{6}$

$\frac{1}{4}$

$\frac{1}{6}$

$\frac{7}{4}$

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Toatal number of favourable cases that a ball is not green = 20
Total number of cases = 24
Probability $= \frac{20}{24} = \frac{5}{6}$

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