A ball of mass 0.5 kg is attached to string of length 50 cm. The ball is rotated on a horizontal circular path about its vertical axis. The maximum tension that the string can bear is 400 N. The maximum possible value of angular velocity of the ball in rad/s is :

Engineering

Physics

Horizontal Circular Motion

Question

1600

1000

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T = mg cosθ + mω²r
T_max = mg + mω²r

$ω = \sqrt{\frac{400 - 5}{0.5 \times 50 \times 10^{- 2}}} = 40$