A ball of mass 2.5 kg is dropped on a smooth inclined plane having e = 0.5. What is the impulse (in N-sec) exerted by the inclined plane on the ball during 1st collision ?

Engineering

Physics

Collision

Question

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$↓ u = \sqrt{2 \times 10 \times 0 .8} = 4 m / s$

velocity of approach = u cos 37° = $\frac{16}{5}$ m/s
velocity of separation = eu cos 37° = $\frac{8}{5}$
change in momentum = 2.5 $(\frac{8}{5} + \frac{16}{5})$ = 12