Foundation
Physics Foundation
Force and Newtons Law of Motion
Impulse and Momentum
Question

A ball of the mass m is moving with velocity v. It strikes the floor and rebounce with the same velocity. If n such balls strike the floor per sec, then force exerted by the balls on the floor is :

mnv    

mv    

mnv

 2mnv

JEE Advance
College PredictorLive

Know your College Admission Chances Based on your Rank/Percentile, Category and Home State.

Get your JEE Main Personalised Report with Top Predicted Colleges in JoSA

Solution
Verified BY
Verified by Zigyan

100     Change in momentum of ball is, 
Δp =  –mv – mv = –2mv
Change in momentum of floor,
Δp =  2mv 

 So, force exerted by one ball per second. 
 will be F = ΔPΔt =  2mv.
 If n ball strike per second than force exerted by balls on floor will be = 2mnv.