A block of mass 2.0 kg moving at 2.0 m/s collides heads on with another block of equal mass kept at rest. The maximum possible loss in kinetic energy due to the collision is

Engineering

Physics

Acceleration

Collision

Momentum and Energy Conservation for System of Particles

Question

A block of mass 2.0 kg moving at 2.0 m/s collides heads on with another block of equal mass kept at rest. The maximum possible loss in kinetic energy due to the collision is

1 J

None

4 J

2 J

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This is a perfectly inelastic collision where two objects stick together after impact, resulting in maximum kinetic energy loss. The initial total momentum is conserved.

Initial momentum: $m \times 2.0 + m \times 0 = 2 m$ . Final velocity $v_{f} = \frac{2 m}{2 m} = 1 m / s$ .

Initial KE: $\frac{1}{2} \times m \times 2^{2} = 2 m$ . Final KE: $\frac{1}{2} \times 2 m \times 1^{2} = m$ .

Loss: $2 m - m = m$ . For m=2.0 kg, loss is 2.0 J.

Final Answer: 2 J