Engineering
Physics
Parallel Plate Capacitor
Question
A capacitance of 2 μF is required in an electrical circuit across a potential difference of 1.0 kV. A large number of 1 μF capacitors are available which can withstand a potential difference of not more than 300 V. The minimum number of capacitors required to achieve this is
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Solution
For the system to with ston d 1 kv potential difference
300 ×4 = 1200 V it can with stond 1 KV also
For net capacitance 2 µ F
= 2 µ F
C = 8
minimum capacitors required = 8 × 4 = 32