A Carnot engine, whose efficiency is 40%, takes in heat from a source maintained at a temperature of 500 K. It is desired to have an engine of efficiency 60%. Then, the intake temperature for the same exhaust (sink) temperature must be :

Engineering

Physics

Heat engine Refrigerator Entropy

Question

efficiency of Carnot engine cannot be made larger than 50%

1200 K

600 K

750 K

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$0 .4 = 1 - \frac{T_{sink}}{500} \Rightarrow T_{sink} = 300 K$

$0 .6 = 1 - \frac{300}{T_{source}} \Rightarrow T_{source} = 750 K$