Engineering
Physics
Lorentz Force

Question

A charged particle (electron or proton) is introduced at the origin (x = 0, y = 0, z = 0) with a given initial velocity ν→. A uniform electric field E→ and a uniform magnetic field B→ exist everywhere. The velocity ν→, electric field E→ and magnetic field B→ are given in columns 1, 2 and 3, respectively. The quantities E0, B0 are positive in magnitude.

Column 1

Column 2

Column 3

(I) Electron with ν→=2E0B0x⌢

(i) E→=E02z⌢ 

(P) B→=–B0x⌢

(II) Electron with ν→=E0B0y⌢

(ii) E→=–E0y⌢

(Q) B→=B0x⌢

(III) Proton with ν→=0

(iii) E→=–E0x⌢

(R) B→=B0y⌢

(IV) Proton with ν→=2E0B0x⌢

(iv) E→=E0x⌢

(S) B→=B0z⌢

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Linked Question 1

In which case will the particle move in a straight line with constant velocity ?

(IV) (i) (S)

(III) (ii) (R)

(III) (iii) (P)

(II) (iii) (S)

Solution

Felectro = q × E = – q E0 x                                                                                               

Fnet = EElectro + Fmagnetic = 0

Hence particle will move along straight line

Linked Question 2

In which case will the particle descirbe a helical path with axis along the positive z direction?

(IV) (ii) (R)

(II) (ii) (R)

(III) (iii) (P)

(IV) (i) (S)

Solution

Force and velocity are perpendicular to each other.

Linked Question 3

In which case would the particle move in a straight line along the negative direction of y-axis (i.e., move along – y⌢)?

(II) (iii) (Q)

(III) (ii) (P)

(III) (ii) (R)

(IV) (ii) (S)

Solution

F→=qvB=q(v→×B→)

F→=qE→