A child with mass m is standing at the edge of a mery-go-round having moment of inertia I, radius R and initial angular velocity ω as shown in the figure. The child jumps off the edge of the merry-go-round with tangential velocity v with respect to the ground. The new angular velocity of the merry-go-round is :

Engineering

Physics

Conservation of Angular Momentum

Question

$\sqrt{\frac{{Iω}^{2} - {mv}^{2}}{I}}$

$\sqrt{\frac{(I + {mR}^{2}) ω^{2} - {mv}^{2}}{I}}$

$\frac{Iω - mvR}{I}$

$\frac{(I + {mR}^{2}) ω - mvR}{I}$

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