A closed vessel with rigid walls contains 1 mol of _{92}^{238} U and 1 mol of air at 298 K. Considering complete decay of _{92}^{238} U \textrm{ }\textrm{ } to \left(\textrm{ }\right)_{82}^{206} Pb, the ratio of the final pressure to the initial pressure of the system at 298K is

Engineering

Chemistry

Application of Radioactivity

Question

A closed vessel with rigid walls contains 1 mol of $_{92}^{238} U$ and 1 mol of air at 298 K. Considering complete decay of $_{92}^{238} U to_{82}^{206} Pb$ , the ratio of the final pressure to the initial pressure of the system at 298K is

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In conversion of $_{92}^{238} U {to}_{82}^{206} Pb$ , 8 α - particles and 6 β particles are ejected.

The number of gaseous moles initially = 1 mol

The number of gaseous moles finally = 1 + 8 mol; (1 mol from air and 8 mol of ₂He⁴)

So the ratio = 9/1 = 9