Engineering
Mathematics
Conjugate Modulus and Argument of a Complex Number
Question

A complex number z is said to be unimodular if |z| = 1. Suppose z1 and z2 are complex numbers such that z12z22z1z¯2 is unimodular and z2 is not unimodular. Then the point z1 lies on a

straight line parallel to y-axis

straight line parallel to x-axis

circle of radius 2

circle of radius

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Solution

⇒  |z1 – 2z2| = |2 – z1z¯2|

|z1|22z1z¯22z2z¯1+4|z1|2=42z¯1z¯22z1z¯2+|z1|2|z2|2

(|z2|2 – 1) (|z1|2 – 4) = 0 ⇒ |z1| = 2.