A container has two immiscible liquids of densities ρ1 and ρ2 (ρ2 > ρ1). A capillary of radius r is inserted in the liquid so that its bottom reaches upto the denser liquid. The denser liquid rises in the capillary and attains a height equal to h, which is equal to the column length of the lighter liquid. Assuming zero contact angle, find the surface tension of the heavier liquid?

Engineering

Physics

Surface Tension

Question

A container has two immiscible liquids of densities ρ₁ and ρ₂ (ρ₂ > ρ₁). A capillary of radius r is inserted in the liquid so that its bottom reaches upto the denser liquid. The denser liquid rises in the capillary and attains a height equal to h, which is equal to the column length of the lighter liquid. Assuming zero contact angle, find the surface tension of the heavier liquid?

$\frac{{rρ}_{2} gh}{2}$

2πr(ρ₂ – ρ₁)gh

2πrρ₂gh

$\frac{r}{2} (ρ_{2} - ρ_{1}) gh$

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