A cylindrical rod with one end in a steam chamber and the outer end in ice results in melting of 0.1 gm of ice per second. If the rod is replaced by another with half the length and double the radius of the first and if the thermal conductivity of material of second rod is 1/4 that of first, the rate at which ice melts is gm/sec will be
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\[ P_1 = k \cdot \pi r^2 \cdot \frac{\Delta T}{L} = 0.1 L_f \] \[ P_2 = \frac{k}{4} \cdot \pi (2r)^2 \cdot \frac{\Delta T}{L/2} = 2k \pi r^2 \cdot \frac{\Delta T}{L} \] \[ P_2 = 2 \cdot 0.1 L_f = 0.2 L_f \] \[ \frac{dm_2}{dt} = \boxed{0.2} \, \text{gm/sec} \]