Engineering
Physics
Thermodynamics
Question

A diatomic ideal gas is compressed adiabatically to  132 of its initial volume. In the initial temperature of gas is Ti (in Kelvin) and the final temperature is  αTi, the value of α is 

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Solution

 T0V07/5=T(V032)7/5=T(V032)2/5

 I=T0×(322/5)=4T0