A die is thrown. Let A be the event that the number obtained is greater than 3. Let B be the event that the number obtained is less than 5. Then P(A ⋃ B) is

Engineering

Mathematics

Basic Definitions Related to Probability

Question

$\frac{2}{5}$

$\frac{3}{5}$

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We have

P(A) = $\frac{3}{6} = \frac{1}{2}$

P(B) = $\frac{4}{6} = \frac{2}{3}$

P(A ⋂ B) = Probability of getting 4 = $\frac{1}{6}$

P(A ⋃ B) = P(A) + P(B) – P(A ⋂ B) = $\frac{1}{2} + \frac{2}{3} - \frac{1}{6} = 1$

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