Engineering
Physics
Center of Mass
Question

A Diwali rocket explodes at the topmost point of its trajectory, at horizontal distance 550 m from the point of projection see figure. When the fragments strike the ground one of the fragments is found at a location 550 m east and 120m north of the launch point. Second fragment is found at a location 550m east and 60 m south of the launch point. First two fragments are of equal mass m and third fragment has mass 2m. If all the three fragments struck the ground simultaneously, what is the location of the third fragment with respect to origin when it strikes ground ? Taking x-axis as east and y-axis as north, point of projection as origin express your answer as xi^+yj^ (in m). Fill |x| + |y| in your answer sheet.

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Solution

C.M. will land at  Range point since top most point is at 550 meters in x direction range 1100 meters so

m(550i^+120j^)+m(550i^60j^)+2m(xi^yj^)=(1100i^)(4m)

x=33002,2y+60=0,y=30,x=1650

Ans. 1680