A fair dice has faces numbered 0, 1, 7, 3, 5 and 9. If it is thrown, the probability of getting an odd number is :

Engineering

Mathematics

Basic Definitions Related to Probability

Question

$\frac{2}{3}$

$\frac{5}{6}$

$\frac{1}{6}$

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A fair dice has faces numbered as 0, 1, 7, 3, 5, 9

Since 1, 3, 5, 7, 9 are odd numbers.

Number of favorable outcomes = 5

Total number of possible outcomes = 6

So, the probability of getting an odd number P(E) =

\frac{Favourable outcomes}{Total number of possible outcomes} = \frac{5}{6}

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