A force acts on a 2 kg object so that its position is given as a function of time as x = 3t2 + 5. What is the work done by this force in first 5 seconds?

Engineering

Physics

Work Done by a Constant Force

Question

A force acts on a 2 kg object so that its position is given as a function of time as x = 3t² + 5. What is the work done by this force in first 5 seconds?

950 J

850 J

900 J

875 J

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x = 3t² + 5

⇒ v = 6t

$\Rightarrow ΔW = Δk$

$= \frac{1}{2} (2) (30^{2}) - \frac{1}{2} 2 {(0)}^{2} = 900 J$