A game of chance consists of spinning an arrow which is equally likely to come to rest pointing to one of the number 1, 2, 3,.....12 as shown in figure.What is the probability that it will point to multiple of 4 ?

Engineering

Mathematics

Conditional Probability

Question

A game of chance consists of spinning an arrow which is equally likely to come to rest pointing to one of the number 1, 2, 3,.....12 as shown in figure.
What is the probability that it will point to multiple of 4 ?

$\frac{1}{3}$

$\frac{1}{4}$

$\frac{1}{6}$

$None of these$

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Total numbers = 12

Multiples of 4 = 4, 8, 12 = 3 numbers

So, the probability

= \frac{Number of multiples of 4}{Total numbers} = \frac{3}{12} = \frac{1}{4}

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