A gas absorbs a photon of 355 nm and emits at two wavelengths. If one of the emissions is at 680 nm, the other is at :

Engineering

Chemistry

Hydrogen Spectrum

Question

518 nm

743 nm

1035 nm

325 nm

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E = E₁ + E₂

_{$\frac{hc}{λ} = \frac{hc}{λ_{1}} + \frac{hc}{λ_{2}}$}

_{$\frac{1}{λ} = \frac{1}{λ_{1}} + \frac{1}{λ_{2}}$}

_{$\frac{1}{355} = \frac{1}{680} + \frac{1}{λ_{2}}$}

λ₂ = 742.76 nm.