Engineering
Physics
Physical Quantities
Question

A horizontal stretched string, fixed at two ends, is vibrating in its fifth harmonic according to the equation, y(x, t) = (0.01 m) sin [(62.8 m–1) x] cos [(628 s–1)t]. Assuming p = 3.14, the correct statement(s) is (are)

The length of the string is 0.25 m

The fundamental frequency is 100 Hz

The number of nodes is 5

The maximum displacement of the midpoint of the string, from its equilibrium position is 0.01 m

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Solution
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(A) 6

(B)  5λ2=L

 K=2πλλ=2πK=0.1m

 L=5λ2

= 5 × 0.1  12  = 0.25 m

(C)  antinode is at mid point

          0.01 m

(D) w = 628 = 2πf5 

f5 = 40 Hz

fundamental = 8 Hz

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