A horizontal stretched string, fixed at two ends, is vibrating in its fifth harmonic according to the equation, y(x, t) = (0.01 m) sin [(62.8 m–1) x] cos [(628 s–1)t]. Assuming p = 3.14, the correct statement(s) is (are)
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(A) 6
(B)
= 5 × 0.1 = 0.25 m
(C) antinode is at mid point
0.01 m
(D) w = 628 = 2f5
f5 = 40 Hz
fundamental = 8 Hz
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