A large tank is filled with water (density = 103 kg/m3). A small hole is made at a depth 10m below water surface. The range of water issuing out of the hole is R on ground. What extra pressure must be applied on the water surface so that the range becomes 2R. (take 1 atm = 105 Pa and g = 10 m/s2)

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v to be doubled
⟹ heff to be 4 times
Δp = 4hρg – hρg = 3 × 10 × 103 × 10 = 3 atm