Foundation
Physics Foundation
Force and Newtons Law of Motion
Impulse and Momentum
Question

A machine gun fires n bullets per second and the mass of each bullet is m. If the speed of bullet is v, then the force exerted on the machine gun is :

mnv    

mnvg

mnvg

mng    

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Solution
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Momentum of one bullet = mv
then rate of change of momentum of n bullet i.e.
Force exerted F=ΔPΔt=nmv