A man (mass = 50 kg) and his son (mass = 20 kg) are standing on a frictionless surface facing each other. The man pushes his son so that he starts moving at a speed of 0.70 ms–1 with respect to the man. The speed of the man with respect to the surface is :

Engineering

Physics

Momentum and Energy Conservation for System of Particles

Question

A man (mass = 50 kg) and his son (mass = 20 kg) are standing on a frictionless surface facing each other. The man pushes his son so that he starts moving at a speed of 0.70 ms^–1 with respect to the man. The speed of the man with respect to the surface is :

0.28 ms^–1

0.20 ms^–1

0.14 ms^–1

0.47 ms^–1

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⇒ 0 = 50V₁ – 20V₂ and V₁ + V₂ = 0.7

⇒ V₁ = 0.2