A metal rod of length 2 m has cross sectional areas 2A and A as shown in the adjacent figure. The ends of the rod are maintained at 100°C and 70°C. The temperature of middle point C is

Engineering

Physics

Conduction of Heat

Question

95°C

8°C

90°C

85°C

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$\frac{k \times 2 A}{1} (100 - T) = \frac{k \times A}{1} (T - 70)$

200 – 2T = T – 70
3T = 270
T = 90°C