A meter bridge is set-up as shown, to determine an unknown resistance 'X' using a standard 10 ohm resistor. The galvanometer shows null point when tapping-key is at 52 cm mark. The end-corrections are 1 cm and 2 cm respectively for the ends A and B. The determined value of 'X' is

Engineering

Physics

Physical Quantities

Question

10.6 ohm

11.1 ohm

10.2 ohm

10.8 ohm

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$\frac{x}{10} = \frac{52 + 1}{48 + 2}$

$= \frac{53 \times 10}{50} = 10.6$

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