Engineering
Mathematics
Introduction to Determinants
Question

A=1    23    4,B=2    13    4 then |(BTAT)–1| is equal to

10

110

1

– 1

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Solution
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A=1    23    4B=2    13    4

BTAT=2    31    41    32    4=2+6    6+121+8    3+16=8    189    19

det(BTAT) = 8 × 19 – 9 × 18 = 152 – 162 = – 10

BTAT1=1detBTATadjBTAT=110191898

detBTAT1=19×818×910=1

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