A number from 2 to 13 is chosen at random. What is the probability that the number chosen is not even?

Engineering

Mathematics

Conditional Probability

Question

$\frac{1}{5}$

$\frac{3}{4}$

$\frac{5}{6}$

$\frac{1}{2}$

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P (getting odd number) = $\frac{6}{12} = \frac{1}{2}$

P (getting not an even number) = 1 – P (getting odd number) =

1 - \frac{1}{2} = \frac{1}{2}

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