Engineering
Physics
Parallel Plate Capacitor
Question

A parallel plate capacitor is of area 6 cm2 and a separation 3mm. The gap is filled with three dielectric materials of equal thickness (see figure) with dielectric constants K1 = 10, K2 = 12 and K3 = 14. The dielectric constant of a material which when fully inserted in above capacitor, gives same capacitance would be :

14

12

4

36

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Solution

Cnet = C1 + C2 + C3

kAE0d=k1(A3)E0d+k2(A3)E0d+k3(A3)E0d

k=k1+k2+k33=12