A parallel plate capacitor of capacitance 90 pF is connected to a battery of emf 20 V. If a dielectric material of dielectric constant K = is inserted between the plates, the magnitude of the induced charge will be

Engineering

Physics

Parallel Plate Capacitor

Conductor

Question

A parallel plate capacitor of capacitance 90 pF is connected to a battery of emf 20 V. If a dielectric material of dielectric constant K = $\frac{5}{3}$ is inserted between the plates, the magnitude of the induced charge will be

0.72 nC

0.3 nC

0.9 nC

2.4 nC

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Q_ind = Q $(1 - \frac{1}{k})$ = 90 × 10^–12 × 20 × $(1 - \frac{1}{5 / 3})$ = 0.72 nC