Engineering
Physics
Horizontal Circular Motion
Question

A particle moves such that its position vector r→(t)=cosωti^+sinωtj^ where w is a constant and t is time. Then which of the following statements is true for the velocity v→(t) and acceleration a→(t) of the particle:

v→ is perpendicular to r→  and  a→ is directed towards the origin.

v→  and  a→ both are parallel to r→

v→  and  a→ both are perpendicular to r→

v→ is perpendicular to r→  and  a→ is directed away from the origin

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Solution

r→=cosωti^+sinωtj^

v→=dr→dt=ω(−sinωti^+cosωtj^)

a→=dv→dt=−ω2(cosωti^+sinωtj^)

a→=−ω2r→           ∴   a→  is  antiparallel  to  r→

v→⋅r→=ω(−sinωtcosωt+cosωtsinωt)=0

So v→⊥r→