Engineering
Physics
Position Vector
Relative Motion
Angular Momentum and Conservation of Angular Momentum
Question
A particle of mass 2 kg is moving along a line 4y – 3x + c = 0 with a constant speed of 5 m/s. If angular momentum about origin is 80 kg m2/S, then c is
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Solution
r⊥ = sin 53° =
L = mv λ⊥
80 = 2 × 5 ×
4y = 3x – C
y = x –