Engineering
Physics
Collision
Question

A “particle” of mass m1 = 2kg, moving with a velocity v1=3i^+2j^k^ m sec–1 undergoes perfectly inelastic collision with a second particle of mass m2 = 3 kg, moving with a velocity v2=-2i^+2j^+4k^ m sec–1. Find the kinetic energy (in J)of the composite particle after collision.

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Solution

m1v1=m2v2=(m1+m2)v

v=2j^+2k^

KE=12m1+m2v2

=12(5)22+22=20J