A particle starts from the origin at time t = 0 and moves along the positive x-axis. The graph of velocity with respect to time is shown in figure. What is the position of the particle at time t = 5s?

Engineering

Physics

Straight Line Motion

Question

9 m

6 m

3 m

10 m

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r_t = 5 = area

$= (\frac{1}{2} \times 2 \times 2 + 2 \times 2 + 3 \times 1) m$

= (2 + 4 + 3) m

= 9 m.