A person in a lift is holding a water jar, which has a small hole at the lower end of its side. When the lift is at rest, the water jet coming out of the hole hits the floor of the lift at a distance d of 1.2 m from the person. In the following, state of the lift's motion is given in List-1 and the distance where the water jet hits the floor of the lift is given in List-II. Match the statements from List-I with those in List-II and select the correct answer using the code given below the lists. List I List II (P) Lift is acceleration vertically up. (1) d = 1.2 m (Q) Lift is accelerating vertically down with an acceleration less than the gravitational acceleration (2) d > 1.2 m (R) Lift is moving vertically up with constant speed. (3) d < 1.2 m (S) Lift is falling freely. (4) No water leaks out of the jar

Engineering

Physics

Liquid Pressure

Question

A person in a lift is holding a water jar, which has a small hole at the lower end of its side. When the lift is at rest, the water jet coming out of the hole hits the floor of the lift at a distance d of 1.2 m from the person. In the following, state of the lift's motion is given in List-1 and the distance where the water jet hits the floor of the lift is given in List-II. Match the statements from List-I with those in List-II and select the correct answer using the code given below the lists.

List I	List II
(P) Lift is acceleration vertically up.	(1) d = 1.2 m
(Q) Lift is accelerating vertically down with an acceleration less than the gravitational acceleration	(2) d > 1.2 m
(R) Lift is moving vertically up with constant speed.	(3) d < 1.2 m
(S) Lift is falling freely.	(4) No water leaks out of the jar

P → 2

Q → 3

R → 1

S → 4

P → 1

Q → 1

R → 1

S → 4

P → 2

Q → 3

R → 2

S → 4

P → 2

Q → 3

R → 1

S → 1

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$y = \frac{1}{2} {gt}^{2}$

$t = \sqrt{\frac{2 y}{g}}$

$d = \sqrt{2 gh} \times \sqrt{\frac{2 y}{g}} = 2 \sqrt{yh}$

P → 1 Q → 1 R → 1 S → 4