A piece of sodium weighs 0.023 g. The number of atoms present in it are -

Foundation

Chemistry Foundation

Mole Concept and Calculation

Question

6.023 × 10²⁰

60.23 × 10²²

6.023 × 10¹⁹

6.023 × 10²¹

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∵ 23g of Na contains = 6.023 × 10²³ atoms.
∴ 0.023 g of Na will contain.
$= \frac{6 .023 \times 10^{23}}{23} \times .0.023$
= 6.023 × 1020 atoms.