A potentiometer wire AB having length L and resistance 12r is joined to a cell D of emf e and internal resistance r. A cell C having emf ε/2 and internal resistance 3r is connected. The length AJ at which the galvanometer as shown in figure shows no deflection is:

Engineering

Physics

Wheatstone Bridge and Meter Bridge and Potentiometer

Question

$\frac{11}{12} L$

$\frac{5}{12} L$

$\frac{13}{24} L$

$\frac{11}{24} L$

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V_AJ = IR_AJ

$\frac{E}{3} = (\frac{E}{12 r + 3 r}) \times (\frac{x}{L} \times 12 r)$