A projectile is given an initial velocity of , where is along the ground and is along the vertical. If g = 10 m/s2, the equation of its trajectory is :

Engineering

Physics

Projectile Motion

Question

A projectile is given an initial velocity of $(\hat{i} + 2 \hat{j}) m / s$ , where $\hat{i}$ is along the ground and $\hat{j}$ is along the vertical. If g = 10 m/s², the equation of its trajectory is :

4y = 2x – 25x²

4y = 2x – 5x²

y = 2x – 5x²

y = x – 5x²

LiveFree JEE Main Previous Year Online Papers Live Free JEE Advance Previous Year Online Papers

College PredictorLive

Know your College Admission Chances Based on your Rank/Percentile, Category and Home State.

Get your JEE Main Personalised Report with Top Predicted Colleges in JoSA

x = t

y = 2t – 5t²