A proton is either released at rest or launched with a certain velocity in a uniform electric field. Which of the graphs in figure could possibly show how the kinetic energy of the proton changes during the proton's motion?
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A proton in a uniform electric field experiences constant force F = qE, so constant acceleration a = qE/m. Kinetic energy KE = (1/2)mv². If released from rest (initial KE=0), KE increases quadratically with time since v = at, so KE = (1/2)m(a²t²) ∝ t². If launched with initial velocity, KE still increases quadratically. The graph must be a parabola opening upwards, starting from zero or positive value.
Equation:
Final answer: The correct graph is the one showing a parabolic increase (upward opening curve), which is the first image (top-left).